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Spring Deflection Determines Frequency

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Author: s_noonan

Group: Default

Filesize: 115.22 kB

Date added: 2025-11-06

Rating: 5

Downloads: 155

Views: 84

Comments: 4

Ratings: 1

Times favored: 0

Made with: Algodoo v2.2.4

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In a vertical spring-mass system under gravity, the undamped natural frequency depends only on the static spring deflection when the system is at rest.
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2025/11/06 13:38:21
verry cool!
Xray
2025/11/06 17:36:02
Interesting simulation!

Q1: Turning Algodoo gravity On or Off seems to have little to no effect on any of the results. Is that correct?

Q2: In the formula, what is the constant "C" from?
s_noonan
2025/11/06 20:53:47
Q1: Turning Algodoo gravity On or Off seems to have little to no effect on any of the results. Is that correct?
A1: The natural frequency would not change, but I would expect to find the spring deflection due to gravity would be zero.

Q2: In the formula, what is the constant "C" from?
A2: C = g^0.5/(2*math.pi) where g = 9.8 m/s2.

So, if somebody sits on a tree branch, you should be able to calculate the natural frequency by how much the branch sags directly under the person and after measuring the actual frequency you can calculate the damping factor for the tree branch.
Last edited at 2025/11/07 11:16:34 by s_noonan
Xray
2025/11/07 16:29:29
Excellent! Thanks.