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DISTANCE CALCULATION (for lololoer)

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Author: Xray

Group: Default

Filesize: 11.16 kB

Date added: 2013-05-14

Rating: 5

Downloads: 531

Views: 572

Comments: 6

Ratings: 1

Times favored: 0

Made with: Algodoo v2.1.0

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lololoer was having trouble calculating the distance between two geometries, so I created this scene for him.

The Thyme calculation is: ((Geom1pos(0) - Geom2pos(0))^2 + (Geom1pos(1) - Geom2pos(1))^2)^0.5

In plain language, you subtract the X position values of the two geometries and square the result. You add that result to the subtracted and squared Y position values of the geometries, and then you take the square root (^0.5) of the summation. The answer is the distance (always a positive value) between the objects.
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This scene is a response to:
Title Author Rating Downloads Comments Date added
Distance calculator (help) lololoer 5 (1 vote) 551 2 2013/05/13 14:54:04
show grid
faytree
2013/05/14 07:15:13
tutorial thread pls :3
Xray
2013/05/14 08:16:11
No tutorial for this. Just a scene. Sorry....
s_noonan
2013/05/14 10:06:44
math.vec.dist(scene.my.greenball,scene.my.redball)­

also works
lololoer
2013/05/14 15:27:20
thankx xray you helped me a lot _o_ , about s_noonan's method i will try it later thnx too. I a asked my teacher that how to calculate the distance between two objects in this type of plane, x,y coordinate axis, and he give me this formula : distance = square root of (x2-x1)^2+(y2-y1)^2
Xray
2013/05/14 19:10:12
s_noonan - Thanks for the tip! I'll try using that on future scenes.

lololoer - That formula that your teacher gave you is the same formula that I used in my example scene for you. Your teacher just laid it out a little differently, but it works the same way.
lololoer
2013/05/15 14:58:12
yes he told me that the square root of a number is the same that elevated to 0.5