Holography. Is it possible or do you need 3 Dimensions?

[xplane80]

Holography. Is it possible or do you need 3 Dimensions?

I was wondering if it was possible because this would be cool.

[Bronie12345]

i think this is possible in phun/algodoo by spawning and deleting on the right moments

[Conundrumer]

With holography, you just need to make the picture change depending on the angle in which you are looking. By angle, I mean the position of the camera.

[Bronie12345]

thats why you need spawning at the right places, or an high-resolution screen in algodoo/phun that changes the image depending on the camera pos

[standardtoaster]

Or a modifiable textureMatrix. As you move the camera it changes the position and stretching of the texture.

[xplane80]

Ok thanks for the advice everyone. I forgot about texturematrix so I might use that.

[xplane80]

Guys, This isn't as easy as I thought it was gonna be.

I've just realised that I've had to go into Arc Lengths (http://en.wikipedia.org/wiki/Arc_length) which is not that easy, fractals and also creating a new branch of holography, 2d holograph. *Yay*

All this maths is hurting my head. Also, I've not even started to make it yet!

[standardtoaster]

Of course it isn't going to be easy. I'll look into the arc length after school.

[xplane80]

Arc Length isn't difficult, it is just a little hard to calculate.

Technically a 2d hologram is just like a 3d model engine on a computer however Algodoo is limited to code so...

[standardtoaster]

You could fake the entire thing. Have a huge texture with every angle possible and modify the position of the textureMatrix to look like it is seamlessly rotating!

[xplane80]

I could but where's the fun in that?!

[xplane80]

I've got think of this like a pencil. If you rotate it one way you see it go like this
_ \|/_\|/_
however if you rotate it another way it will look like this
_._._._

so all I have to do is create an algorithm that fill's in all of the gaps that join this
.
to this
\
or this
|
to this
- (\ and .)

[xplane80]

I have just figured out an algorithm for a 1d lines length for what angle they are viewed about.
Example:
If you are viewing a line that is 1 unit in length at 1m to right (which is 45º), the length of the line will look like it is 1/(2^0.5) units.

The algorithm are quite simple for 1d:

Cos*Viewing_Angle = Length of the Line
Tan*Viewing angle = Viewing Length