v2.0.1b15 Parse substitution into list member

[tatt61880]

I know next code works well.

Code: Select all

e.this.color = [e.this.color(0), e.this.color(1), e.this.color(2), 0];

But I feel it's not smart.

So I suggest to parse next code correctly.

Code: Select all

e.this.color(3) = 0;

(NOTE: The code above won't work well in v2.0.1b15)

[tatt61880]

Is this difficult to be implemented?

[Ivan]

I highly support that suggestion.