v2.0.1b15 Parse substitution into list member
3 posts • Page 1 of 1
v2.0.1b15 Parse substitution into list member
I know next code works well.
So I suggest to parse next code correctly.
(NOTE: The code above won't work well in v2.0.1b15)
- Code: Select all
e.this.color = [e.this.color(0), e.this.color(1), e.this.color(2), 0];
So I suggest to parse next code correctly.
- Code: Select all
e.this.color(3) = 0;
(NOTE: The code above won't work well in v2.0.1b15)
NOTE: I'm not an Algoryx member.
Hi, Algodoo lovers. Have you read next topic? Featured scenes suggestions
To translators: English.cfg changelog will be useful (even for me).
Hi, Algodoo lovers. Have you read next topic? Featured scenes suggestions
To translators: English.cfg changelog will be useful (even for me).
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tatt61880 - [Most Helpful Person 2010]
- Posts: 1150
- Joined: Mon Aug 31, 2009 5:45 pm
- Location: Tokyo, Japan
Re: v2.0.1b15 Parse substitution into list member
Is this difficult to be implemented?
NOTE: I'm not an Algoryx member.
Hi, Algodoo lovers. Have you read next topic? Featured scenes suggestions
To translators: English.cfg changelog will be useful (even for me).
Hi, Algodoo lovers. Have you read next topic? Featured scenes suggestions
To translators: English.cfg changelog will be useful (even for me).
-
tatt61880 - [Most Helpful Person 2010]
- Posts: 1150
- Joined: Mon Aug 31, 2009 5:45 pm
- Location: Tokyo, Japan
Re: v2.0.1b15 Parse substitution into list member
I highly support that suggestion.
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Ivan - Posts: 202
- Joined: Tue Oct 06, 2009 2:01 pm
- Location: Croatia
3 posts • Page 1 of 1
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