Decimal/bits converter

[Matten]

Is there a formula to get the number of bits needed to make a certain amount of numbers? So 2 will give 1, 4 will give 2, 8 will give 3 etc

[monstertje3]

in binary i dont think 8 will result in 3, it is more likely it will have 0001 as output;

Code: Select all

2^0,2^1,2^2,2^3
0   0   0   1

[Matten]

I don't mean a binary number, but the number of bits. With 3 bits there are 2^3 = 8 possible combinations, with 4 bits there are 2^4 = 16 possible combinations etc... But I want the reverse, so how many bits do you need to get 8 or 16 possible combinations.

I also like your sig

[Ivan]

You can do this via logarithms.

2ˣ = Y
X = log₂(Y)

[Matten]

Thanks! I tested it with some graphing app, but does Algodoo know the log2 function? I thought I've seen the log function somewhere, but not log2.

[monstertje3]

log2 is the same as log Y / log 2
if i am understanding that log2(Y) 2logY is

[Matten]

Log(y)/log(2) nearly crashed that app...
I'll start my comp now to try it in Algodoo, and otherwise I suggest adding a logN(base,power) function

Edit: I searched for "log" in the console, but that also doesn't give any logarithm related stuff. Anyone any ideas?

[monstertje3]

according to the functions list in the thyme section, there isn't a log function
maybe make a suggestion in the suggestion forum

[emilk]

No need, I'll add Math.log (natural base) and Math.log10 (nice to have) in next version.